(D) The $pH$ is calculated using the formula: $pH = -\log [H^{+}]$.Given $[H^{+}] = 2 \times 10^{-9} \ M$.$pH = -\log (2 \times 10^{-9})$$pH = -(\log

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(D) The $pH$ is calculated using the formula: $pH = -\log [H^{+}]$.Given $[H^{+}] = 2 \times 10^{-9} \ M$.$pH = -\log (2 \times 10^{-9})$$pH = -(\log 2 + \log 10^{-9})$$pH = -(\log 2 - 9)$$pH = 9 - \log 2$Since $\log 2 \approx 0.301$,$pH = 9 - 0.301 = 8.699 \approx 8.7$.

Class 11 Chemistry 6-2.Equilibrium-II (Ionic Equilibrium)Water hydrolysis and pH scale

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The hydrogen ion concentration of the oceans is about $2 \times 10^{-9} \ M.$ What is the $pH$?

A
$8.85$
B
$9.3$
C
$7.85$
D
$8.7$

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6-2.Equilibrium-II (Ionic Equilibrium)

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Water hydrolysis and pH scale

The $pH$ in the stomach is approximately:

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What is the $pH$ of the solution containing $1.342 \times 10^{-3} \ M \ H^{+}$ ions?
$(\log 1.342 = 0.1277)$

MediumMHT CET 2022

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Which equation represents the $pH$ of a solution?

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If the ionic product of water $(K_w)$ is $1.96 \times 10^{-14}$ at $35^{\circ} C$, what is its value at $10^{\circ} C$?

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The hydrogen ion concentration of the oceans is about $2 \times 10^{-9} \ M.$ What is the $pH$?

Similar Questions

The $pH$ in the stomach is approximately:

What is the $pH$ of the solution containing $1.342 \times 10^{-3} \ M \ H^{+}$ ions?$(\log 1.342 = 0.1277)$

Which equation represents the $pH$ of a solution?

If the ionic product of water $(K_w)$ is $1.96 \times 10^{-14}$ at $35^{\circ} C$, what is its value at $10^{\circ} C$?

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What is the $pH$ of the solution containing $1.342 \times 10^{-3} \ M \ H^{+}$ ions?
$(\log 1.342 = 0.1277)$